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Unit 6 Electrochemistry

6.1 Exercises

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Section 6.1 Exercises

  1. For each of the following balanced half-reactions, determine whether an oxidation or reduction is occurring.

    (a) Fe3++3eFe

    (b) CrCr3++3e

    (c) MnO24MnO4+e

    (d) Li++eLi

  2. Given the following pairs of balanced half-reactions, determine the balanced reaction for each pair of half-reactions in an acidic solution.

    (a) CaCa2++2e,F2+2e2F

    (b) LiLi++e,Cl2+2e2Cl

    (c) FeFe3++3e,Br2+2e2Br

    (d) AgAg++e,MnO4+4H++3eMnO2+2H2O

  3. Identify the species that undergoes oxidation, the species that undergoes reduction, the oxidizing agent, and the reducing agent in each of the reactions.

    (a) H2O2+Sn2+H2O+Sn4+

    (b) PbO2+HgHg2+2+Pb2+

    (c) Al+Cr2O27Al3++Cr3+

  4. Identify the species that was oxidized, the species that was reduced, the oxidizing agent, and the reducing agent in each of the reactions.

    (a) SO23(aq)+Cu(OH)2(s)SO24(aq)+Cu(OH)(s)

    (b) O2(g)+Mn(OH)2(s)MnO2(s)

    (c) NO3(aq)+H2(g)NO(g)

    (d) Al(s)+CrO24(aq)Al(OH)3(s)+Cr(OH)4(aq)

  5. Why is it not possible for hydrogen ion (H+) to appear in either of the half-reactions or the overall equation when balancing oxidation-reduction reactions in basic solution?

Solutions

  1. (a) reduction; (b) oxidation; (c) oxidation; (d) reduction
  2. (a) F2+Ca2F+Ca2+; (b) Cl2+2Li2Li++2Cl; (c) 3Br2+2Fe2Fe+3+6Br; (d) MnO4+4H++3Ag3Ag++MnO2+2H2O
  3. Oxidized: (a) Sn2+; (b) Hg; (c) Al; reduced: (a) H2O2; (b) PbO2; (c) Cr2O72−; oxidizing agent: (a) H2O2; (b) PbO2; (c) Cr2O72−; reducing agent: (a) Sn2+; (b) Hg; (c) Al
  4. Oxidized = reducing agent: (a) SO32−; (b) Mn(OH)2; (c) H2; (d) Al; reduced = oxidizing agent: (a) Cu(OH)2; (b) O2; (c) NO32−; (d) CrO42−
  5. In basic solution at 298.15 K, [OH] > 1.0 × 10−7M > [H+]. Hydrogen ion cannot appear as a reactant because its concentration is essentially zero. If it were produced, it would instantly react with the excess hydroxide ion to produce water. Thus, hydrogen ion should not appear as a reactant or product in basic solution.

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